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x^2-2.455x+1.500=0
We add all the numbers together, and all the variables
x^2-2.455x+1.5=0
a = 1; b = -2.455; c = +1.5;
Δ = b2-4ac
Δ = -2.4552-4·1·1.5
Δ = 0.027025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.455)-\sqrt{0.027025}}{2*1}=\frac{2.455-\sqrt{0.027025}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.455)+\sqrt{0.027025}}{2*1}=\frac{2.455+\sqrt{0.027025}}{2} $
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